跳转至

LeetCode: 185. 部门工资前三高的员工

1、题目描述

Employee 表包含所有员工信息,每个员工有其对应的 Id, salary 和 department Id 。

+----+-------+--------+--------------+
| Id | Name  | Salary | DepartmentId |
+----+-------+--------+--------------+
| 1  | Joe   | 70000  | 1            |
| 2  | Henry | 80000  | 2            |
| 3  | Sam   | 60000  | 2            |
| 4  | Max   | 90000  | 1            |
| 5  | Janet | 69000  | 1            |
| 6  | Randy | 85000  | 1            |
+----+-------+--------+--------------+

Department 表包含公司所有部门的信息。

+----+----------+
| Id | Name     |
+----+----------+
| 1  | IT       |
| 2  | Sales    |
+----+----------+

编写一个 SQL 查询,找出每个部门工资前三高的员工。例如,根据上述给定的表格,查询结果应返回:

+------------+----------+--------+
| Department | Employee | Salary |
+------------+----------+--------+
| IT         | Max      | 90000  |
| IT         | Randy    | 85000  |
| IT         | Joe      | 70000  |
| Sales      | Henry    | 80000  |
| Sales      | Sam      | 60000  |
+------------+----------+--------+

2、解题思路

​ 之前,我们找出了部门第N高的薪水,这里使用的思路差不多,如果在部门里面,大于当前工资的数量少于3个,就表示当前工资是前3高的

# Write your MySQL query statement below
select d.Name as Department , e.Name as Employee , e.Salary from Employee e , Department d where e.DepartmentId = d.Id and (select count(distinct Salary) from Employee where DepartmentId = d.id and  Salary > e.Salary ) < 3  order by Department